150.0 grams of AsF₃ were reacted with 180.0 g of CCl₄ to produce AsCl₃ and CCl₂F₂. The theoretical yield of CCl₂F₂, in grams, is ,Hint: Don't forget to include the coefficients from the balanced reaction in your consideration.

Question

Quizplus · Accepted Answer

The balanced reaction is:2AsF3 + 3CCl4 → 2AsCl3 + 3CCl2F2From the balanced reaction, we can see that 2 moles of AsF3 react with 3 moles of CCl4 to produce 3 moles of CCl2F2.Therefore, the mole ratio of AsF3 to CCl2F2 is 2:3.The molar mass of AsF3 is 144.91 g/mol, and the molar mass of CCl2F2 is 120.91 g/mol.Therefore, the mass ratio of AsF3 to CCl2F2 is (2 x 144.91 g/mol) / (3 x 120.91 g/mol) = 1.91.This means that for every 1.91 g of AsF3 that reacts, 1 g of CCl2F2 is produced.Therefore, the theoretical yield of CCl2F2 is:150.0 g AsF3 x (1 g CCl2F2 / 1.91 g AsF3) = 78.53 g CCl2F2However, the question asks for the theoretical yield in grams, so we need to multiply the answer by 2 to get the final answer:78.53 g CCl2F2 x 2 = 157.06 g CCl2F2Therefore, the correct answer is A) 141.4 grams.

1500 Grams of AsF3 Were Reacted with 180

1500 Grams of AsF₃ Were Reacted with 180