In a chemical equation, C₂H₆O + PCl₃ $\rarr$ C₂H₅Cl + H₃PO₃, when the reaction was carried out, the actual yield of C₂H₅Cl was calculated as 97.3 % of the theoretical value. If the theoretical yield should have been 2.04 moles, how many grams of C₂H₅Cl were actually obtained?

Question

Quizplus · Accepted Answer

The theoretical yield is 2.04 moles. The actual yield is 97.3% of this, which is 1.98492 moles. The molar mass of C2H5Cl is approximately 64.5 g/mol. Therefore, the actual yield in grams is 1.98492 moles * 64.5 g/mol = 128 grams.

In a Chemical Equation, C2H6O + PCl3 →\rarr→ C2H5Cl + H3PO3, When the Reaction Was Carried Out, the H3PO3

In a Chemical Equation, C₂H₆O + PCl₃ $\rarr$ C₂H₅Cl + H₃PO₃, When the Reaction Was Carried Out, the H₃PO₃