In a chemical equation, C₃H₆O₂ + PCl₃ $\rarr$C₃H₅OCl + H₃PO₃, when the reaction was carried out, the actual yield of C₃H₅OCl was calculated as 97.3 % of the theoretical value. If the theoretical yield should have been 1.42 moles, how many grams of C₃H₅OCl were actually obtained?

Question

Quizplus · Accepted Answer

The actual yield is 97.3% of the theoretical yield. The molar mass of C3H5OCl is approximately 92.52 g/mol. The actual moles obtained are 1.42 moles * 0.973 = 1.38166 moles. Therefore, the actual grams obtained are 1.38166 moles * 92.52 g/mol = 127.8 grams, which rounds to 128 grams.

In a Chemical Equation, C3H6O2 + PCl3 →\rarr→ C3H5OCl + H3PO3, When the Reaction Was Carried Out, the H3PO3

In a Chemical Equation, C₃H₆O₂ + PCl₃ $\rarr$ C₃H₅OCl + H₃PO₃, When the Reaction Was Carried Out, the H₃PO₃