In a chemical equation, AsF₃ + CCl₄ $\rarr$ AsCl₃ + CCl₂F₂, the theoretical yield of CCl₂F₂ was calculated to be 1.68 moles. If the percent yield in the reaction was 74.3%, how many grams of CCl₂F₂ were obtained?

Question

Quizplus · Accepted Answer

The actual yield is 74.3% of the theoretical yield. The molar mass of CCl₂F₂ is approximately 120.91 g/mol. Actual yield in moles = 1.68 moles * 0.743 = 1.24824 moles. Grams = 1.24824 moles * 120.91 g/mol = 151 grams.

In a Chemical Equation, AsF3 + CCl4 →\rarr→ AsCl3 + CCl2F2, the Theoretical Yield of CCl2F2 Was Calculated

In a Chemical Equation, AsF₃ + CCl₄ $\rarr$ AsCl₃ + CCl₂F₂, the Theoretical Yield of CCl₂F₂ Was Calculated