In a chemical equation, AsF₃ + C₂Cl₆ $\rarr$ AsCl₃ + C₂Cl₂F₄, the theoretical yield of C₂Cl₂F₄ was calculated to be 1.86 moles. If the percent yield in the reaction was 77.2%, how many grams of C₂Cl₂F₄ were actually obtained?

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The Answer of In a chemical equation, AsF₃ + C₂Cl₆ $\rarr$ AsCl₃ + C₂Cl₂F₄, the theoretical yield of C₂Cl₂F₄ was calculated to be 1.86 moles. If the percent yield in the reaction was 77.2%, how many grams of C₂Cl₂F₄ were actually obtained?

In a Chemical Equation, AsF3 + C2Cl6 →\rarr→ AsCl3 + C2Cl2F4, the Theoretical Yield of C2Cl2F4 Was Calculated

In a Chemical Equation, AsF₃ + C₂Cl₆ $\rarr$ AsCl₃ + C₂Cl₂F₄, the Theoretical Yield of C₂Cl₂F₄ Was Calculated