Use the Following Standard Enthalpies of Atom Combination To $\Delta$ H_ac° H₂(g) = -435

Use the following standard enthalpies of atom combination to
$\Delta$ H_ac° H₂(g) = -435.30 kJ/mol_rxn   $\Delta$ H_ac F₂(g) = -157.98 kJ/mol_rxn
$\Delta$ H_ac° N₂(g) = -945.41 kJ/mol_rxn   $\Delta$ H_ac° C(s) = -716.68 kJ/mol_rxn
$\Delta$ H_ac° O₂(g) = -498.34 kJ/mol_rxn   $\Delta$ H_ac° NH₃(g) = -1171.8 kJ/mol_rxn
$\Delta$ H_ac° H₂O(g) = -926.3 kJ/mol_rxn   $\Delta$ H_ac° HF(g) = -567.7 kJ/mol_rxn
-What is $\Delta$ H_rxn° for the following reaction?
3 N(g) $\rightarrow$ 3/2 N₂(g)

A) +710 kJ/mol_rxn
B) -710 kJ/mol_rxn
C) +1418 kJ/mol_rxn
D) -1418 kJ/mol_rxn
E) -473 kJ/mol_rxn