Use the Following Standard Enthalpies of Atom Combination To $\Delta$ H_ac° H₂(g) = -435

Use the following standard enthalpies of atom combination to
$\Delta$ H_ac° H₂(g) = -435.30 kJ/mol_rxn   $\Delta$ H_ac F₂(g) = -157.98 kJ/mol_rxn
$\Delta$ H_ac° N₂(g) = -945.41 kJ/mol_rxn   $\Delta$ H_ac° C(s) = -716.68 kJ/mol_rxn
$\Delta$ H_ac° O₂(g) = -498.34 kJ/mol_rxn   $\Delta$ H_ac° NH₃(g) = -1171.8 kJ/mol_rxn
$\Delta$ H_ac° H₂O(g) = -926.3 kJ/mol_rxn   $\Delta$ H_ac° HF(g) = -567.7 kJ/mol_rxn
-What is the $\Delta$ H_rxn° for the following reaction as written?
4 NH₃(g) + 3 O₂(g) $\rightarrow$ 2 N₂(g) + 6 H₂O(g)

A) -1266 kJ/mol_rxn
B) -1184 kJ/mol_rxn
C) -196 kJ/mol_rxn
D) +767 kJ/mol_rxn
E) none of the above