An electron is moving at $3.0 \times 10^{6} \mathrm{~m} / \mathrm{s}$ perpendicular to a uniform magnetic field. If the radius of the motion is $18 \mathrm{~mm}$, what is the magnitude of the magnetic field?
A) $70 \mathrm{mT}$
B) $8.9 \mathrm{nT}$
C) $1.6 \mu \mathrm{T}$
D) $9.3 \mathrm{mT}$
E) $0.95 \mathrm{mT}$

Question

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The Answer of An electron is moving at $3.0 \times 10^{6} \mathrm{~m} / \mathrm{s}$ perpendicular to a uniform magnetic field. If the radius of the motion is $18 \mathrm{~mm}$, what is the magnitude of the magnetic field?
A) $70 \mathrm{mT}$
B) $8.9 \mathrm{nT}$
C) $1.6 \mu \mathrm{T}$
D) $9.3 \mathrm{mT}$
E) $0.95 \mathrm{mT}$

An Electron Is Moving At 3.0×106 m/s3.0 \times 10^{6} \mathrm{~m} / \mathrm{s}3.0×106 m/s

An Electron Is Moving At $3.0 \times 10^{6} \mathrm{~m} / \mathrm{s}$