What is the speed of a proton in a cyclotron having a $0.50 \mathrm{~T}$ magnetic field when the proton is at a distance of $25 \mathrm{~cm}$ from the center?
A) $1.1 \times 10^{4} \mathrm{~m} / \mathrm{s}$
B) $3.2 \times 10^{6} \mathrm{~m} / \mathrm{s}$
C) $3.7 \times 10^{7} \mathrm{~m} / \mathrm{s}$
D) $1.2 \times 10^{7} \mathrm{~m} / \mathrm{s}$
E) $6.0 \times 10^{6} \mathrm{~m} / \mathrm{s}$

Question

Quizplus · Accepted Answer

The speed of a proton in a cyclotron can be calculated using the formula $v = qBr/m$, where $q$ is the charge of the proton, $B$ is the magnetic field, $r$ is the radius, and $m$ is the mass of the proton. Substituting the given values, the speed is approximately $1.2 \times 10^{7} \mathrm{~m} / \mathrm{s}$.

What Is the Speed of a Proton in a Cyclotron 0.50 T0.50 \mathrm{~T}0.50 T

What Is the Speed of a Proton in a Cyclotron $0.50 \mathrm{~T}$