Find the Force (Magnitude and Direction) Exerted on an Electron $2.0 \times$

Find the force (magnitude and direction) exerted on an electron moving vertically upward at a speed of $2.0 \times$ $10^{7} \mathrm{~m} / \mathrm{s}$ by a horizontal magnetic field of $0.50 \mathrm{~T}$ directed north.

A) $1.6 \times 10^{-12} \mathrm{~N}$ west
B) $1.8 \times 10^{-12} \mathrm{~N}$ east
C) $1.6 \times 10^{-12} \mathrm{~N}$ east
D) $1.8 \times 10^{-12} \mathrm{~N}$ west