What is the molality of KBr in a solution made by dissolving 2.21 g of KBr in 897 g of water?

Question

Quizplus · Accepted Answer

Molality (m) is defined as the number of moles of solute per kilogram of solvent. To find the molality of KBr in the solution, first, calculate the moles of KBr. The molar mass of KBr (K = 39.1 g/mol + Br = 79.9 g/mol) is approximately 119 g/mol. Thus, $2.21 \, \text{g KBr} \times \frac{1 \, \text{mol KBr}}{119 \, \text{g KBr}} = 0.0186 \, \text{mol KBr}$. Since the mass of the water (solvent) is 897 g, or 0.897 kg, the molality is $0.0186 \, \text{mol} / 0.897 \, \text{kg} = 0.0207 \, \text{m}$.

What Is the Molality of KBr in a Solution Made