Calculate the molality of a solution prepared by dissolving 12.1 g of CH₃OH in 475 g of water.

Question

Quizplus · Accepted Answer

Molality (m) is calculated using the formula $m = \frac{\text{moles of solute}}{\text{kg of solvent}}$. The molar mass of CH3OH (methanol) is approximately 32.04 g/mol (12.01 for C, 4.04 for H, and 16.00 for O). Thus, $12.1 \, \text{g CH3OH} \times \frac{1 \, \text{mol}}{32.04 \, \text{g}} = 0.3777 \, \text{mol CH3OH}$. The mass of water is 475 g, which is 0.475 kg. Therefore, $m = \frac{0.3777 \, \text{mol}}{0.475 \, \text{kg}} = 0.795 \, \text{m}$.

Calculate the Molality of a Solution Prepared by Dissolving 12