A student wishes to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl. What volume of the 12.0 M HCl should he/she start with?

Question

Quizplus · Accepted Answer

The correct answer is A.To prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl, we can use the formula:M1V1 = M2V2where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.Plugging in the values we know:12.0 M * V1 = 0.875 M * 65.0 mLSolving for V1:V1 = (0.875 M * 65.0 mL) / 12.0 M = 4.74 mLTherefore, the student should start with 4.74 mL of 12.0 M HCl.

A Student Wishes to Prepare 65