If 50.0 mL of a 6.0 M HCl is diluted to 200. mL, what will be the new concentration of the solution?

Question

Quizplus · Accepted Answer

The concentration after dilution can be calculated using the formula $C_1V_1 = C_2V_2$, where $C_1$ and $C_2$ are the initial and final concentrations, and $V_1$ and $V_2$ are the initial and final volumes. Substituting the given values: $6.0\,M \times 50.0\,mL = C_2 \times 200.0\,mL$. Solving for $C_2$ gives $C_2 = 1.5\,M$.

If 500 ML of a 6