How many grams of KCl (molar mass = 74.55 g) will be produced from the reaction of 50.0 mL of 0.300 M KOH with excess HCl?
KOH (aq) + HCl (aq) $\rightarrow$ KCl (aq) + HCl (l)

Question

Quizplus · Accepted Answer

First, calculate the moles of KOH using its concentration and volume (0.300 M * 0.050 L = 0.015 moles). Since the reaction is 1:1, the moles of KCl produced will also be 0.015. Then, convert moles of KCl to grams (0.015 moles * 74.55 g/mol = 1.11825 g), which rounds to 1.12 g.

How Many Grams of KCl (Molar Mass = 74 →\rightarrow→ KCl (Aq) + HCl (L) A) 1

How Many Grams of KCl (Molar Mass = 74 $\rightarrow$ KCl (Aq) + HCl (L)
A) 1