What volume of 8.25 M HCl must be diluted to prepare 2.40 L of 0.500 M HCl?

Name: What volume of 8.25 M HCl must be diluted to prepare 2.40 L of 0.500 M HCl?
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Question

Quizplus · Accepted Answer

To find the volume of the concentrated solution needed, use the dilution equation M1V1 = M2V2. Here, M1 = 8.25 M, M2 = 0.500 M, and V2 = 2.40 L. Solving for V1 gives V1 = (M2 * V2) / M1 = (0.500 M * 2.40 L) / 8.25 M = 0.145 L, which is 145 mL.

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