In a classroom taste-test for PTC the genotype frequency was determined to be P = .35 and Q = .65.After applying the Hardy-Weinberg equation,the percentage of genotypes were found to be as follows:
D)none of the above

Question

Quizplus · Accepted Answer

The Hardy-Weinberg equation predicts the genotype frequencies of a population based on the allele frequencies. The equation is p^2 + 2pq + q^2 = 1, where p and q are the frequencies of the two alleles (in this case, P and Q). 
Plugging in the given allele frequencies, p = 0.35 and q = 0.65, we can solve for the expected genotype frequencies: 
PP = (0.35)^2 = 0.1225
PQ = 2(0.35)(0.65) = 0.455
QQ = (0.65)^2 = 0.4225
When we convert these to percentages, we get:
PP = 12.25%
PQ = 45.5%
QQ = 42.25%
The only answer choice that matches these percentages is B.

In a Classroom Taste-Test for PTC the Genotype Frequency Was