A system containing an ideal gas at a constant pressure of 1.42 × 10⁵ Pa gains 2320 J of heat.During the process,the internal energy of the system increases by 2540 J.What is the change in volume of the gas?

Question

Quizplus · Accepted Answer

The first law of thermodynamics for a constant pressure process is:
ΔU= Q - PΔV
where ΔU is the change in internal energy, Q is the heat added to the system, P is the constant pressure, and ΔV is the change in volume.

Substituting the given values, we get:

2540 J = 2320J - (1.42 × 10⁵ Pa)(ΔV)

Simplifying and solving for ΔV, we get:
ΔV = -(2540 J) / (1.42 × 10⁵ Pa) = -1.55 × 10⁻² m³

Therefore, the change in volume of the gas is -1.55 × 10⁻² m³, which corresponds to choice B.

A System Containing an Ideal Gas at a Constant Pressure