Using the following equation for the combustion of octane,calculate the heat of reaction for 400.0 g of octane.The molar mass of octane is 114.33 g/mole. 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O ΔH°_rxn= -11018 kJ

Question

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First, calculate the moles of octane: 400.0 g / 114.33 g/mol = 3.498 moles. Since the reaction involves 2 moles of octane, the heat of reaction for 3.498 moles is (3.498/2) * -11018 kJ = -19280 kJ.

Using the Following Equation for the Combustion of Octane,calculate the Heat