At 1 atm pressure,the heat of sublimation of gallium is 277.0kJ/mol and the heat of vaporization is 271.0 kJ/mol.To the correct number of significant figures,how much heat is required to melt 5.50 mol of gallium at 1 atm pressure?

Question

Quizplus · Accepted Answer

The heat of fusion can be calculated by subtracting the heat of vaporization from the heat of sublimation: 277.0 kJ/mol - 271.0 kJ/mol = 6.0 kJ/mol. For 5.50 mol, the heat required is 5.50 mol * 6.0 kJ/mol = 33 kJ.

At 1 Atm Pressure,the Heat of Sublimation of Gallium Is