The isomerization of methylisonitrile to acetonitrile CH₃NC(g) → CH₃CN(g)
Is first order in CH₃NC.The half life of the reaction is 5.20 × 10¹ s at 545 K.The rate constant when the initial [CH₃NC] is 0.030 M is ________ .

Question

The isomerization of methylisonitrile to acetonitrile CH₃NC(g) → CH₃CN(g)
Is first order in CH₃NC.The half life of the reaction is 5.20 × 10¹ s at 545 K.The rate constant when the initial [CH₃NC] is 0.030 M is ________

The isomerization of methylisonitrile to acetonitrile CH<sub>3</sub>NC(g) → CH<sub>3</sub>CN(g) Is first order in CH<sub>3</sub>NC.The half life of the reaction is 5.20 × 10<sup>1</sup> s at 545 K.The rate constant when the initial [CH<sub>3</sub>NC] is 0.030 M is ________ . A) 75.1 B) 0.641 C) 0.0133 D) 1.56 E) 2.84 × 10<sup>4</sup>

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Quizplus · Accepted Answer

The rate law for the reaction is: Rate = k [CH₃NC] Given half-life, t1/2 = 5.20 × 10¹ s We can use the relation t1/2 = 0.693/k to find the value of rate constant k. t1/2 = 0.693/k k = 0.693/t1/2 At initial [CH₃NC] = 0.030 M, the rate of the reaction is: Rate = k [CH₃NC] = (0.693/5.20 × 10¹ s) × (0.030 M) = 0.0133 M/s Therefore, the answer is choice C.

The Isomerization of Methylisonitrile to Acetonitrile CH3NC(g)→ CH3CN(g)

The Isomerization of Methylisonitrile to Acetonitrile CH₃NC(g)→ CH₃CN(g)