The value of ΔG° at 221.0°C for the formation of calcium chloride from its constituent elements: Ca(s) + Cl₂(g) → CaCl₂(s)
Is ________ kJ/mol.At 25.0°C for this reaction,ΔH° is -795.8 kJ/mol,ΔG° is -748.1 kJ/mol,and ΔS° is -159.8 J/K.

Question

Quizplus · Accepted Answer

To find ΔG° at 221.0°C, use the equation ΔG° = ΔH° - TΔS°. Convert 221.0°C to Kelvin (494.15 K) and ΔS° to kJ (by dividing by 1000). Then, ΔG° = -795.8 kJ/mol - (494.15 K * -0.1598 kJ/K/mol) = -716.8 kJ/mol.

The Value of ΔG° at 221