For a particular reaction,the value of ∆H is -48.6 kJ/mol and ∆S is -254J/mol K.When is this reaction spontaneous (assuming that ∆H and ∆S do not vary as the temperature changes).

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Quizplus · Accepted Answer

The reaction is spontaneous when ∆G is negative. ∆G = ∆H - T∆S. So, ∆G is negative when ∆H < T∆S. In this case, ∆H = -48.6 kJ/mol and ∆S = -254J/mol K. So, ∆G is negative when T > 191K. Therefore, the reaction is spontaneous at T > 191K.

For a Particular Reaction,the Value of ∆H Is -48