A sample of solid silver releases 476 J of heat when cooled from 98.3°C to 21.2°C.The specific heat of silver is 0.24 J/g • °C.What is the mass of the sample?

Question

Quizplus · Accepted Answer

We can use the formula for heat released by a substance during cooling, which is:
Q = mcΔT
where Q is the heat released, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature (final temperature minus initial temperature).

We are given Q = 476 J, c = 0.24 J/g • °C, ΔT = 98.3°C - 21.2°C = 77.1°C (note that we need to use the absolute temperature difference in Kelvin for the Celsius-to-Kelvin conversion, but this cancels out in the calculation). We can rearrange the formula to solve for m:

m = Q / cΔT

Plugging in the values, we get:

m = 476 J / (0.24 J/g • °C × 77.1°C) = 25.7 g

Therefore, the answer is E: 25.7 g, which is the mass of the sample of solid silver.

A Sample of Solid Silver Releases 476 J of Heat