A 0.140-kg baseball is thrown with a velocity of 27.1 m/s. It is struck by the bat with an average force of 5000 N,which results in a velocity of 37.0 m/s in the opposite direction from the original velocity.How long were the bat and ball in contact? A)1.79 × 10^-3 s B)1.28 × 10^-2 s C)3.07 × 10^-2 s D)4.30 × 10^-3 s

Question

Quizplus · Accepted Answer

The impulse-momentum theorem states that the change in momentum equals the impulse applied. The change in velocity is 27.1 m/s + 37.0 m/s = 64.1 m/s. The change in momentum is 0.140 kg * 64.1 m/s = 8.974 kg·m/s. The impulse is force * time, so 5000 N * time = 8.974 kg·m/s. Solving for time gives time = 8.974 / 5000 = 1.79 × 10^-3 s.

A 0140-Kg Baseball Is Thrown with a Velocity of 27