A 0.24 kg blob of clay is thrown at a wall with an initial horizontal velocity of 16 m/s. If the clay comes to a stop in 91ms. What is the average horizontal force on the clay due to the wall?
A)42 N
B)26 N
C)35 N
D)51 N

Question

A 0.24 kg blob of clay is thrown at a wall with an initial horizontal velocity of 16 m/s.  If the clay comes to a stop in 91ms.  What is the average horizontal force on the clay due to the wall?
A)42 N
B)26 N
C)35 N
D)51 N

Quizplus · Accepted Answer

The average force can be calculated using the formula F = Δp/Δt, where Δp is the change in momentum and Δt is the time interval. The initial momentum is (0.24 kg)(16 m/s) = 3.84 kg·m/s. The final momentum is 0 kg·m/s since the clay stops. Thus, Δp = 3.84 kg·m/s. The time interval Δt is 91 ms = 0.091 s. Therefore, the average force is F = 3.84 kg·m/s / 0.091 s ≈ 42 N.

A 024 Kg Blob of Clay Is Thrown at a Wall