A steady horizontal force lasting for 2.1 s gives a 1.25 kg object an acceleration of 3.2 m/s² on a frictionless table.What impulse does this force give to the object? A)26 kg ∙ m/s B)11 kg ∙ m/s C)8.4 kg ∙ m/s D)2.6 kg ∙ m/s

Question

Quizplus · Accepted Answer

Impulse is calculated as the product of force and time. The force can be found using F = ma, where m = 1.25 kg and a = 3.2 m/s². Thus, F = 1.25 kg * 3.2 m/s² = 4 N. The impulse is then 4 N * 2.1 s = 8.4 kg∙m/s.

A Steady Horizontal Force Lasting for 2