FIGURE 20-7
-Two identical charges of magnitude 6.0 μC are placed at the corners of the base of an equilateral triangle, as shown in Figure 20-7. What is the electric potential at the vertex, P, of the triangle due to these charges?

Question

FIGURE 20-7 
-Two identical charges of magnitude 6.0 μC are placed at the corners of the base of an equilateral triangle, as shown in Figure 20-7. What is the electric potential at the vertex, P, of the triangle due to these charges?

Quizplus · Accepted Answer

The electric potential at a point due to a point charge is given by V = kQ/r. For two identical charges, the total potential is the sum of potentials due to each charge. Here, V = 2(k * 6.0 μC / r). Assuming r is the side of the equilateral triangle, the calculation gives 54 kV.

FIGURE 20-7 -Two Identical Charges of Magnitude 6.0 μC Are Placed at Are