A +8.00-μC charge is situated along the +y-axis at y = 0.400 m. What is the electric potential at the origin because of this charge?

Question

Quizplus · Accepted Answer

The electric potential at the origin due to a point charge is given by:V = kq/rwhere k is Coulomb's constant, q is the charge, and r is the distance from the charge to the point where the potential is being calculated.In this case, q = +8.00 μC = +8.00 × 10^-6 C, and r = 0.400 m. Substituting these values into the equation, we get:V = (9 × 10^9 N·m^2/C^2)(+8.00 × 10^-6 C)/(0.400 m) = +180 × 10^3 VTherefore, the electric potential at the origin due to the +8.00-μC charge is +180 × 10^3 V.

A +800-μC Charge Is Situated Along the +Y-Axis at Y =