A 4.0-μC charge is situated at the origin of an xy-coordinate system. What is the magnitude and direction of the electric potential at x = 6.0 m?

Question

Quizplus · Accepted Answer

The electric potential at a point a distance r away from a point charge q is given by:

V = kq/r

where k is the Coulomb constant (k = 9 x 10^9 N m^2/C^2).

In this case, the point charge is located at the origin (r = 6.0 m), and q = 4.0 μC = 4.0 x 10^-6 C. Substituting these values into the equation gives:

V = (9 x 10^9 N m^2/C^2)(4.0 x 10^-6 C)/(6.0 m) = 6.0 x 10^3 V

Since the electric potential is a scalar quantity, it has no direction, so the answer is (E) 6000 V with no direction.

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