A 60.0-μF capacitor is in series with a 100-Ω resistor connected across an ac source of frequency 120 Hz. What is the phase angle?
A) -12.4°
B) +12.4°
C) -77.6°
D) +77.6°
E) 90.0°

Question

Quizplus · Accepted Answer

The phase angle is given by:$$\phi = \arctan\left(\frac{X_C}{R}\right)$$where:$$X_C = \frac{1}{2\pi fC}$$is the capacitive reactance.Substituting the given values, we get:$$X_C = \frac{1}{2\pi (120 Hz)(60.0 \mu F)} = 212.2 \Omega$$$$\phi = \arctan\left(\frac{212.2 \Omega}{100 \Omega}\right) = -12.4°$$

A 600-μF Capacitor Is in Series with a 100-Ω Resistor Connected