A 100-Ω resistor is connected in series with a 10-mH inductor across an ac source operating at 1000 Hz. What is the impedance of this circuit?
A) 100 Ω
B) 118 Ω
C) 200 Ω
D) 236 Ω
E) 1000 Ω

Question

Quizplus · Accepted Answer

The impedance of a series RL circuit is calculated using the formula Z = √(R² + (XL)²), where XL = 2πfL. Here, R = 100 Ω, f = 1000 Hz, and L = 10 mH = 0.01 H. First, calculate XL = 2π(1000)(0.01) = 62.83 Ω. Then, Z = √(100² + 62.83²) ≈ 118 Ω.

A 100-Ω Resistor Is Connected in Series with a 10-MH