A 120-V rms voltage at 1000 Hz is applied to a resistor and an inductor in series. If the impedance of this circuit is 110 Ω, what is the maximum value of the current?
A) 1.54 A
B) 1.09 A
C) 1.84 A
D) 1.04 A
E) None of the other answers is correct.

Question

Quizplus · Accepted Answer

The maximum current can be found using Ohm's law and the impedance of the circuit:

I(max) = V(max) / Z

Where V(max) is the maximum voltage, which for an RMS voltage is V(max) = sqrt(2)*V(rms).

Thus, V(max) = sqrt(2)*120 V = 169.7 V

Plugging in the given values, we get:

I(max) = 169.7 V / 110 Ω = 1.54 A

Therefore, the answer is choice A, 1.54 A.

A 120-V Rms Voltage at 1000 Hz Is Applied to a Resistor