Find ΔH° for the reaction C₃H₈(g)+ 5 O₂(g)→ 3 CO₂(g)+ 4 H₂O(l). ΔH° = -2046 kJ for the reaction: C₃H₈(g)+ 5 O₂(g)→ 3 CO₂(g)+ 4 H₂O(g),and the heat of vaporization of water is 44.0 kJ/mol.Note that H₂O is a liquid in the first reaction and a gas in the second.

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Quizplus · Accepted Answer

The heat of vaporization of water is 44.0 kJ/mol. So, the enthalpy change for the reaction C₃H₈(g)+ 5 O₂(g)→ 3 CO₂(g)+ 4 H₂O(l) is:ΔH° = -2046 kJ - 4(44.0 kJ/mol) = -2222 kJ

Find ΔH° for the Reaction C3H8(g)+ 5 O2(g)→ 3 CO2(g)

Find ΔH° for the Reaction C₃H₈(g)+ 5 O₂(g)→ 3 CO₂(g)