Find ΔH for C3H8 (g) + 6 H2O (g) → 3 CO2 (g) + 10 H2
Given C3H8 (g) + 3 H2O (g) → 3 CO (g) + 7 H2 (g) ΔH = 499 kJ
CO (g) + H2O (g) → CO2 (g) + H2 (g) ΔH = -41 kJ
A) 376 kJ
B) 458 kJ
C) 540 kJ
D) 622 kJ
Correct Answer:
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