How much water must be added to 42.0 g of CaCl₂ to produce a solution that is 35.0 wt% CaCl₂? A)56.7 g B)78.0 g C)83.3 g D)120 g

Question

Quizplus · Accepted Answer

Let x be the amount of water to be added to 42.0 g of CaCl2.

The mass of the resulting solution is (42.0 g + x).

Since the desired solution is 35.0% CaCl2 by weight, we have:

0.35(42.0 g + x) = 42.0 g

14.7 g + 0.35x = 42.0 g

0.35x = 27.3 g

x = 78.0 g

Therefore, 78.0 g of water must be added to 42.0 g of CaCl2 to produce a solution that is 35.0% CaCl2 by weight.

How Much Water Must Be Added to 42