How many moles of KOH are present in 67.2 mL of 0.487 M KOH?

Question

Quizplus · Accepted Answer

First, we need to convert the given volume of solution into moles of KOH using its molarity:

(67.2 mL) x (0.487 mol/L) = 32.7 mmol KOH

Since 1 mole = 1000 mmol, we can convert mmol to moles:

32.7 mmol / 1000 = 0.0327 mol

Therefore, there are 0.0327 moles of KOH present in 67.2 mL of 0.487 M KOH.

The closest answer choice to this value is C, which is 0.033 mol (rounded to three significant figures).

How Many Moles of KOH Are Present in 67