What volume of 0.330 M Na₂CO₃ (106 g/mol)solution contains 32.7 of Na₂CO₃?

Question

Quizplus · Accepted Answer

First, we need to use the formula: moles = concentration x volume to find the number of moles of Na₂CO₃ in the solution: moles = 0.330 mol/L x volume moles = 32.7 g / 106 g/mol moles = 0.308 mol Then, we can rearrange the formula to solve for volume: volume = moles / concentration volume = 0.308 mol / 0.330 mol/L volume = 0.934 L Therefore, the answer is (C) 0.934 L.

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