What mass of Na₂CO₃ is present in 0.450 L of a 0.704 M Na₂CO₃ solution?

Name: What mass of Na 2 CO 3 is present in 0.450 L of a 0.704 M Na 2 CO 3 solution?
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Question

Quizplus · Accepted Answer

First, calculate the molar mass of Na2CO3 (sodium carbonate): Na = 22.99 g/mol, C = 12.01 g/mol, O = 16.00 g/mol. So, Na2CO3 = (2*22.99) + 12.01 + (3*16.00) = 105.99 g/mol. Then, use the molarity formula: mass = molarity * volume * molar mass. Here, mass = 0.704 mol/L * 0.450 L * 105.99 g/mol = 33.5 g.

What Mass of Na2CO3 Is Present in 0

What Mass of Na₂CO₃ Is Present in 0