In order to prepare a standard 1.00 M solution of oxalic acid from H₂C₂O₄ · 2H₂O (126.07 g/mol),10.086 g of oxalic acid dihydrate should be dissolved in

Question

Quizplus · Accepted Answer

To prepare a standard 1.00 M solution of oxalic acid, we need to dissolve 126.07 g/mol of oxalic acid in 1 L (1000 mL) of solution.

First, we need to calculate the number of moles of oxalic acid dihydrate in 10.086 g:

moles = mass / molar mass

moles = 10.086 g / 126.07 g/mol

moles = 0.080 moles

Since 1 mole of oxalic acid dihydrate gives 1 mole of oxalic acid, we have 0.080 moles of oxalic acid.

To make a 1.00 M solution, we need 0.080 moles of oxalic acid in 0.080 L of solution, which is equivalent to 80.0 mL of solution. Therefore, the oxalic acid should be dissolved in enough water to make 80.0 mL of solution, or choice D.

In Order to Prepare a Standard 1