A 18-kg mass is placed on a 28° incline and friction keeps it from sliding.The coefficient of static friction in this case is 0.591,and the coefficient of sliding friction is 0.511.What is the frictional force in this situation?
A) 82.81 N
B) 155.75 N
C) 79.59 N
D) 92.05 N
E) 8.45 N

Question

A 18-kg mass is placed on a 28° incline and friction keeps it from sliding.The coefficient of static friction in this case is 0.591,and the coefficient of sliding friction is 0.511.What is the frictional force in this situation?
A) 82.81 N
B) 155.75 N
C) 79.59 N
D) 92.05 N
E) ​8.45 N

Quizplus · Accepted Answer

The frictional force is equal to the component of the gravitational force parallel to the incline, which is m * g * sin(θ). For an 18-kg mass on a 28° incline, this is 18 * 9.8 * sin(28°) = 82.81 N.

A 18-Kg Mass Is Placed on a 28° Incline and Friction