Jamal pulls a 250-N sled up a 25.0° slope at constant speed by a force of 200 N.Near the top of the hill he releases the sled.With what acceleration does the sled go down the hill? A) 7.84 m/s² B) 9.92 m/s² C) 0.88 m/s² D) 0.44 m/s² E) 1.44 m/s²

Question

Quizplus · Accepted Answer

Since the sled is moving at constant speed up the slope, it must be experiencing a force that balances the force of gravity acting on it down the slope. Therefore, we can set up the following equation:

force pulling sled up slope = force of gravity down slope

200 N = mgsin(25°)

Solving for the mass of the sled, we get:

m = 200 N / (9.8 m/s^2) * sin(25°) = 44.22 kg

When Jamal releases the sled, the only force acting on it is the force of gravity down the slope. Using Newton's second law (force = mass x acceleration), we can solve for the acceleration of the sled down the slope:

force of gravity = ma

mg*sin(25°) = ma

a = g*sin(25°) = 0.44 m/s^2

Therefore, the sled accelerates down the slope at a rate of 0.44 m/s^2.

Jamal Pulls a 250-N Sled Up a 25