Hector drives a pickup truck horizontally at 10.0 m/s.He is transporting a crate of delicate lead crystal.If the coefficient of static friction between the crate and the truck bed is 0.700,what is the minimum stopping distance for the truck so the crate will not slide?
A) 7.3 m
B) 14.0 m
C) 100.0 m
D) 17.3 m
E) 3.6 m

Question

Hector drives a pickup truck horizontally at 10.0 m/s.He is transporting a crate of delicate lead crystal.If the coefficient of static friction between the crate and the truck bed is 0.700,what is the minimum stopping distance for the truck so the crate will not slide?
A) 7.3 m
B) 14.0 m
C) 100.0 m
D) 17.3 m
E) ​3.6 m

Quizplus · Accepted Answer

The minimum stopping distance can be calculated using the formula $ d = \frac{v^2}{2\mu g} $, where $ v = 10.0 \, \text{m/s} $, $ \mu = 0.700 $, and $ g = 9.8 \, \text{m/s}^2 $. Plugging in these values gives $ d = \frac{(10.0)^2}{2 \times 0.700 \times 9.8} = 7.3 \, \text{m} $.

Hector Drives a Pickup Truck Horizontally at 10