What is the internal energy of a monatomic ideal gas with pressure 6 ×10⁵ Pa and with volume 2 m³? A) 6 × 10⁵ J B) 18 × 10⁵ J C) 9 × 10⁵ J D) More information is needed to find this value.

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Quizplus · Accepted Answer

Internal energy of a monatomic ideal gas is given by U = (3/2)PV. Here, P = 6 × 10⁵ Pa and V = 2 m³. So, U = (3/2) × 6 × 10⁵ Pa × 2 m³ = 18 × 10⁵ J.

What Is the Internal Energy of a Monatomic Ideal Gas