An airplane with a wingspan of 68.0 m flies parallel to the Earth's surface at a point where the downward component of the Earth's magnetic field is 0.380 × l0−⁴ T.If the induced potential between wingtips is 0.600 V,what is the plane's speed? A) 33.5 m/s B) 15.5 m/s C) 232 m/s D) 15,800 m/s E) 88 m/s

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Quizplus · Accepted Answer

The induced potential (emf) is given by the formula emf = B * v * L, where B is the magnetic field, v is the speed, and L is the wingspan. Solving for v gives v = emf / (B * L) = 0.600 V / (0.380 × 10^-4 T * 68.0 m) = 232 m/s.

An Airplane with a Wingspan of 68