A 600-turn circular coil with an area of 0.0350 m² is mounted on a rotating frame,which turns at a rate of 21.0 rad/s in the presence of a 0.0650-T uniform magnetic field that is perpendicular to the axis of rotation.What is the instantaneous emf in the coil at the moment that the normal to its plane is at a 75.0° angle to the field? A) zero B) 28.7 V C) 37.5 V D) 27.7 V E) 0.065 V

Question

Quizplus · Accepted Answer

The instantaneous emf induced in a rotating coil is given by:
emf = NBAω sin θ
where N is the number of turns, B is the magnetic field strength, A is the area of the coil, ω is the angular velocity of rotation, and θ is the angle between the plane of the coil and the magnetic field.

We are given N = 600, A = 0.0350 m^2, B = 0.0650 T, ω = 21.0 rad/s, and θ = 75.0°. Plugging these values into the formula above, we get:

emf = NBAω sin θ
= (600)(0.0350)(0.0650)(21.0) sin 75.0°
= 27.7 V

Therefore, the answer is (D) 27.7 V.

A 600-Turn Circular Coil with an Area of 0