A large jetliner with a wingspan of 37 m flies horizontally and due north at a speed of 190 m/s in a region where the magnetic field of the earth is 56 µT directed 55° below the horizontal.What is the magnitude of the induced emf between the ends of the wing?
A) 230 mV
B) 390 mV
C) 320 mV
D) 22 mV
E) 9 mV

Question

A large jetliner with a wingspan of 37 m flies horizontally and due north at a speed of 190 m/s in a region where the magnetic field of the earth is 56 µT directed 55° below the horizontal.What is the magnitude of the induced emf between the ends of the wing?
A) 230 mV
B) 390 mV
C) 320 mV
D) 22 mV
E) ​9 mV

Quizplus · Accepted Answer

The induced emf can be calculated using the equation:

emf = B * l * v * sin(theta)

where B is the magnetic field strength, l is the length of the conductor moving through the magnetic field (in this case, the wingspan of the jetliner), v is the velocity of the conductor, and theta is the angle between the velocity vector and the magnetic field vector.

Plugging in the given values,

emf = (56 x 10^-6 T) * (37 m) * (190 m/s) * sin(55°)
emf = 0.32 V or 320 mV

Therefore, the best choice is C.

A Large Jetliner with a Wingspan of 37 M Flies