A Young's double-slit apparatus is set up where a screen is positioned 1.2 m from the double slits.If the distance between alternating bright fringes is 0.89 cm,and the light source has a wavelength of 576 nm,what is the separation of the double slits? (1 nm = 10−⁹ m) A) 1.0E-2 m B) 7.8E-5 m C) 6.7E-6 m D) 8.3E-5 m E) 4.3E-9 m

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Quizplus · Accepted Answer

The fringe separation (Δy) is given by the formula Δy = (λL) / d, where λ is the wavelength, L is the distance to the screen, and d is the slit separation. Rearranging for d gives d = (λL) / Δy. Substituting the given values: λ = 576 nm = 576 x 10^-9 m, L = 1.2 m, Δy = 0.89 cm = 0.0089 m, we get d = (576 x 10^-9 m * 1.2 m) / 0.0089 m = 7.8 x 10^-5 m.

A Young's Double-Slit Apparatus Is Set Up Where a Screen