A Young's double-slit apparatus is set up.The source wavelength is 442 nm,and the double-slit spacing is 0.0404 mm.At what distance from the double slits should the screen be placed if the spacing between alternating bright fringes is to be 2.80 cm? (1 nm = 10−⁹ m) A) 256 m B) 2.56 m C) 0.326 m D) 234 m E) 2.56 m

Question

Quizplus · Accepted Answer

The fringe spacing (Δy) is given by the formula Δy = (λL) / d, where λ is the wavelength, L is the distance to the screen, and d is the slit spacing. Solving for L gives L = (Δy * d) / λ. Substituting the given values (Δy = 2.80 cm = 0.028 m, λ = 442 nm = 442 x 10^-9 m, d = 0.0404 mm = 0.0404 x 10^-3 m), we find L ≈ 2.56 m.

A Young's Double-Slit Apparatus Is Set Up