A Young's interference experiment is conducted with Blue argon laser light (λ = 499 nm).The separation between the slits is 0.60 mm,and the interference pattern appears on a screen 4.3 m away.What is the spacing between the bright fringes? (1 nm = 10−⁹ m) A) 3.0 mm B) 3.6 mm C) 12 mm D) 7.2 mm E) 2.1 mm

Question

Quizplus · Accepted Answer

The spacing between the bright fringes is given by the equation: 
d = λD/d
where λ is the wavelength of the light, D is the distance from the slits to the screen, and d is the slit separation. 
Substituting the given values: 
d = (499 nm)(4.3 m)/(0.60 mm)
d ≈ 3.6 mm 
Therefore, the best choice is (B) 3.6 mm.

A Young's Interference Experiment Is Conducted with Blue Argon Laser